Cevap:
[tex]f( - 3) \\ 4.( - 3) + 3y = 12 \\ - 12 + 3y = 12 \\ 3y = 12 + 12 \\ 3y = 24 \\ y = 8 \\ f(a) \\ 4a + 3y = 12 \\ 3y = 12 - 4a \\ y = \frac{12 - 4a}{3} \\ 8 + \frac{12 - 4a}{3} = 12 \\ 8 + 4 - \frac{4a}{3} = 12 \\ 12 - \frac{4a}{3} = 12 \\ \frac{ - 4a}{3} = 0 \\ a = 0[/tex]
